What is the d/(dt)(-4.9t^2+x+21) ?

The d/(dt)(-4.9t^2+x+21) is -9.8t+(dx)/(dt)

What is the first d/(dt)(-4.9t^2+x+21) ?

The first d/(dt)(-4.9t^2+x+21) is -9.8t+(dx)/(dt)

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\frac{d}{d t} (- 4.9 t^{2} + x + 21)

- 9.8 t + \frac{d x}{d t}

Solution steps

\frac{d}{d t} (- 4.9 t^{2} + x + 21)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (4.9 t^{2}) + \frac{d x}{d t} + \frac{d}{d t} (21)

\frac{d}{d t} (4.9 t^{2}) = 9.8 t

\frac{d}{d t} (21) = 0

= - 9.8 t + \frac{d x}{d t} + 0

Simplify

= - 9.8 t + \frac{d x}{d t}

y = x^{2} + 2 x - 2

f (x, y) = 98 y^{2} + x^{2} - x^{2} y

f (x) = 4 cos (2 x) - 4, (0, 2 π)

f (x) = 2 x + 9 x^{\frac{2}{9}}

f (x) = x ln (6 x)

What is the d/(dt)(-4.9t^2+x+21) ?
The d/(dt)(-4.9t^2+x+21) is -9.8t+(dx)/(dt)
What is the first d/(dt)(-4.9t^2+x+21) ?
The first d/(dt)(-4.9t^2+x+21) is -9.8t+(dx)/(dt)