d/(dt)(-4.9t^2+x+21)

Lösung

\frac{d}{d t} (- 4.9 t^{2} + x + 21)

- 9.8 t + \frac{d x}{d t}

Schritte zur Lösung

\frac{d}{d t} (- 4.9 t^{2} + x + 21)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (4.9 t^{2}) + \frac{d x}{d t} + \frac{d}{d t} (21)

\frac{d}{d t} (4.9 t^{2}) = 9.8 t

\frac{d}{d t} (21) = 0

= - 9.8 t + \frac{d x}{d t} + 0

Vereinfache

= - 9.8 t + \frac{d x}{d t}

y = x^{2} + 2 x - 2

f (x, y) = 98 y^{2} + x^{2} - x^{2} y

f (x) = 4 cos (2 x) - 4, (0, 2 π)

f (x) = 2 x + 9 x^{\frac{2}{9}}

f (x) = x ln (6 x)