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Popular >

extreme y=x^3-3x^2+5

Solution

extreme points

y = x^{3} - 3 x^{2} + 5

Solution

Maximum (0, 5), Minimum (2, 1)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 0

into

x^{3} - 3 x^{2} + 5 : 5

Maximum (0, 5)

Plug

x = 2

into

x^{3} - 3 x^{2} + 5 : 1

Minimum (2, 1)

Maximum (0, 5), Minimum (2, 1)

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extreme x^3+3xy^2-15x-12y+1 extreme points

x^{3} + 3 x y^{2} - 15 x - 12 y + 1

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y = - x + z

extreme f(x)=x^2-10x-1 extreme points

f (x) = x^{2} - 10 x - 1

Frequently Asked Questions (FAQ)

What is the extreme y=x^3-3x^2+5 ?
The extreme y=x^3-3x^2+5 is Maximum(0,5),Minimum(2,1)