What is the extreme f(x)= 1/4 (x+2)(x-1)^2 ?

The extreme f(x)= 1/4 (x+2)(x-1)^2 is Maximum(-1,1),Minimum(1,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)= 1/4 (x+2)(x-1)^2

extreme points

f (x) = \frac{1}{4} (x + 2) (x - 1)^{2}

Maximum (- 1, 1), Minimum (1, 0)

Solution steps

f^{'} (x) = \frac{3 x ^{2} - 3}{4}

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

\frac{1}{4} (x + 2) (x - 1)^{2} : 1

Maximum (- 1, 1)

Plug

x = 1

into

\frac{1}{4} (x + 2) (x - 1)^{2} : 0

Minimum (1, 0)

Maximum (- 1, 1), Minimum (1, 0)

f (x) = x (ln (x))^{5}

f (x, y) = \frac{e ^{(- x^{2} + y^{2})} ( x + y ^{2} ) + 1}{2}

f (x) = x^{3} - 4500 x^{2} + 6 \cdot 1 0^{6} x

f (x, y) = e^{- (x^{2} + y^{2} - 6 y)}

f (x) = - x^{3} (x - 3)

What is the extreme f(x)= 1/4 (x+2)(x-1)^2 ?
The extreme f(x)= 1/4 (x+2)(x-1)^2 is Maximum(-1,1),Minimum(1,0)