What is the extreme E(a,b)=(a(a+b)^2(a-b))/(a^2-b^2) ?

The extreme E(a,b)=(a(a+b)^2(a-b))/(a^2-b^2) is Saddle(0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme E(a,b)=(a(a+b)^2(a-b))/(a^2-b^2)

extreme points

E (a, b) = \frac{a ( a + b ) ^{2} ( a - b )}{a ^{2} - b ^{2}}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial a ^{2}} = 0

D (a, b) = - 1

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

f (x) = (x^{2} - \frac{7}{3} x + \frac{13}{9}) e^{3 x}

f (x) = 2 x^{5} + 2 x^{4} - x^{3} + 6 x^{2} + 8 x + 4

f (x) = \frac{- 1}{x - 4}

x^{3} - 3 x^{2} + 2 x + 8

x^{3} \cdot e^{- x}

What is the extreme E(a,b)=(a(a+b)^2(a-b))/(a^2-b^2) ?
The extreme E(a,b)=(a(a+b)^2(a-b))/(a^2-b^2) is Saddle(0,0)