What is the extreme f(x)=5+9x^2-6x^3 ?

The extreme f(x)=5+9x^2-6x^3 is Minimum(0,5),Maximum(1,8)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=5+9x^2-6x^3

extreme points

f (x) = 5 + 9 x^{2} - 6 x^{3}

Minimum (0, 5), Maximum (1, 8)

Solution steps

f^{'} (x) = - 18 x^{2} + 18 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = 0

into

5 + 9 x^{2} - 6 x^{3} : 5

Minimum (0, 5)

Plug

x = 1

into

5 + 9 x^{2} - 6 x^{3} : 8

Maximum (1, 8)

Minimum (0, 5), Maximum (1, 8)

f (x, y) = 6 - x^{2} - 4 y^{2}

f (x) = 2 x^{2} + \frac{2048}{x} + 13

f (x) = (x + 3)^{\frac{4}{3}}, - 6 \leq x \leq 6

x y - 2 x - 2 y - x^{2} - y^{2}

f (x) = 25 x - 25 x e^{- y} - 50 y - x^{2}

What is the extreme f(x)=5+9x^2-6x^3 ?
The extreme f(x)=5+9x^2-6x^3 is Minimum(0,5),Maximum(1,8)