What is the extreme f(x)=-2x^3+39x^2-216x+9 ?

The extreme f(x)=-2x^3+39x^2-216x+9 is Minimum(4,-359),Maximum(9,-234)

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extreme f(x)=-2x^3+39x^2-216x+9

extreme points

f (x) = - 2 x^{3} + 39 x^{2} - 216 x + 9

Minimum (4, - 359), Maximum (9, - 234)

Solution steps

f^{'} (x) = - 6 x^{2} + 78 x - 216

Find intervals:

Decreasing

: - \infty < x < 4,

Increasing

: 4 < x < 9,

Decreasing

: 9 < x < \infty

Plug

x = 4

into

- 2 x^{3} + 39 x^{2} - 216 x + 9 : - 359

Minimum (4, - 359)

Plug

x = 9

into

- 2 x^{3} + 39 x^{2} - 216 x + 9 : - 234

Maximum (9, - 234)

Minimum (4, - 359), Maximum (9, - 234)

f (x) = - 2 x^{2} + 12 x - 10

f (x) = y e^{- x}

f (x) = \frac{x + 1}{x ^{2} - 4 x - 5}

f (- \frac{7}{3}, \frac{14}{3}) = x^{2} + x y + y^{2} - 7 y + 16

f (x, y) = 3 x^{2} - 9 x + 9 x y^{2}

What is the extreme f(x)=-2x^3+39x^2-216x+9 ?
The extreme f(x)=-2x^3+39x^2-216x+9 is Minimum(4,-359),Maximum(9,-234)