What is the extreme f(x)=x^3-4x^2+5x ?

The extreme f(x)=x^3-4x^2+5x is Maximum(1,2),Minimum(5/3 , 50/27)

Popular >

extreme f(x)=x^3-4x^2+5x

extreme points

f (x) = x^{3} - 4 x^{2} + 5 x

Maximum (1, 2), Minimum (\frac{5}{3}, \frac{50}{27})

Solution steps

f^{'} (x) = 3 x^{2} - 8 x + 5

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < \frac{5}{3},

Increasing

: \frac{5}{3} < x < \infty

Plug

x = 1

into

x^{3} - 4 x^{2} + 5 x : 2

Maximum (1, 2)

Plug

x = \frac{5}{3}

into

x^{3} - 4 x^{2} + 5 x : \frac{50}{27}

Minimum (\frac{5}{3}, \frac{50}{27})

Maximum (1, 2), Minimum (\frac{5}{3}, \frac{50}{27})

f (x) = \frac{x ^{3}}{3} - 4 x^{2} + 12 x, 0 \leq x \leq 7

f (x, y) = x^{2} + y^{2} - 1

f (x) = 2 x^{3} - 12 x^{2} + 18 x - 5

x^{2} + 4 x y + y^{2}

f (x, y) = x^{3} + x^{2} + y^{2} + y^{3}

What is the extreme f(x)=x^3-4x^2+5x ?
The extreme f(x)=x^3-4x^2+5x is Maximum(1,2),Minimum(5/3 , 50/27)