What is the extreme f(x)= 1/3 x^3+5x^2+24 ?

The extreme f(x)= 1/3 x^3+5x^2+24 is Maximum(-10, 572/3),Minimum(0,24)

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extreme f(x)= 1/3 x^3+5x^2+24

extreme points

f (x) = \frac{1}{3} x^{3} + 5 x^{2} + 24

Maximum (- 10, \frac{572}{3}), Minimum (0, 24)

Solution steps

f^{'} (x) = x^{2} + 10 x

Find intervals:

Increasing

: - \infty < x < - 10,

Decreasing

: - 10 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 10

into

\frac{1}{3} x^{3} + 5 x^{2} + 24 : \frac{572}{3}

Maximum (- 10, \frac{572}{3})

Plug

x = 0

into

\frac{1}{3} x^{3} + 5 x^{2} + 24 : 24

Minimum (0, 24)

Maximum (- 10, \frac{572}{3}), Minimum (0, 24)

f (x) = x ln (x) - 2 x, 1 \leq x \leq 4

f (x) = - 2 x^{2} - 1, - 4 \leq x \leq 3

f (x) = \frac{x}{ln ( 2 x )}

f (x, y) = 4 - x^{2} - y^{2} + x y + x

f (x) = \frac{x ^{2}}{x ^{2} + 3}, - 1 \leq x \leq 1

What is the extreme f(x)= 1/3 x^3+5x^2+24 ?
The extreme f(x)= 1/3 x^3+5x^2+24 is Maximum(-10, 572/3),Minimum(0,24)