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Popular >

extreme y=x^2-6x+10

Solution

extreme points

y = x^{2} - 6 x + 10

Solution

Minimum (3, 1)

Solution steps

f^{'} (x) = 2 x - 6

Find intervals:

Decreasing

: - \infty < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 3

into

x^{2} - 6 x + 10 : 1

Minimum (3, 1)

Popular Examples

extreme f(x)=4x^3-48x-1 extreme points

f (x) = 4 x^{3} - 48 x - 1

extreme f(x)=xsqrt(465-x)extreme points

f (x) = x 465 - x

extreme f(x)= 3/(1-x^2)extreme points

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extreme f(x)=x^2+8x+12 extreme points

f (x) = x^{2} + 8 x + 12

extreme f(x)=5x^{2/3}+9 extreme points

f (x) = 5 x^{\frac{2}{3}} + 9

Frequently Asked Questions (FAQ)

What is the extreme y=x^2-6x+10 ?
The extreme y=x^2-6x+10 is Minimum(3,1)