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Popular >

extreme f(x)=5x^{2/3}+9

Solution

extreme points

f (x) = 5 x^{\frac{2}{3}} + 9

Solution

Minimum (0, 9)

Solution steps

f^{'} (x) = \frac{10}{3 x ^{\frac{1}{3}}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

5 x^{\frac{2}{3}} + 9 : 9

Minimum (0, 9)

Popular Examples

extreme f(x)=3x^2+2 extreme points

f (x) = 3 x^{2} + 2

extreme x^2+x-6 extreme points

x^{2} + x - 6

extreme f(x)= 7/4 x^2-21/2 x+51/4 extreme points

f (x) = \frac{7}{4} x^{2} - \frac{21}{2} x + \frac{51}{4}

derivative of 7x^3y^2+34x^2y^5

\frac{d}{d x} (7 x^{3} y^{2} + 34 x^{2} y^{5})

extreme f(x)=7x^9-9x^7-7,-3<= x<= 3 extreme points

f (x) = 7 x^{9} - 9 x^{7} - 7, - 3 \leq x \leq 3

Frequently Asked Questions (FAQ)

What is the extreme f(x)=5x^{2/3}+9 ?
The extreme f(x)=5x^{2/3}+9 is Minimum(0,9)