What is the extreme f(x)= 7/4 x^2-21/2 x+51/4 ?

The extreme f(x)= 7/4 x^2-21/2 x+51/4 is Minimum(3,-3)

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extreme f(x)= 7/4 x^2-21/2 x+51/4

extreme points

f (x) = \frac{7}{4} x^{2} - \frac{21}{2} x + \frac{51}{4}

Minimum (3, - 3)

Solution steps

f^{'} (x) = \frac{7 x - 21}{2}

Find intervals:

Decreasing

: - \infty < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 3

into

\frac{7}{4} x^{2} - \frac{21}{2} x + \frac{51}{4} : - 3

Minimum (3, - 3)

\frac{d}{d x} (7 x^{3} y^{2} + 34 x^{2} y^{5})

f (x) = 7 x^{9} - 9 x^{7} - 7, - 3 \leq x \leq 3

f (x) = \frac{e ^{x}}{3 + e ^{x}}

f (x) = 8 x^{3} - x^{4}

f (x) = x^{3} - 27

What is the extreme f(x)= 7/4 x^2-21/2 x+51/4 ?
The extreme f(x)= 7/4 x^2-21/2 x+51/4 is Minimum(3,-3)