What is the critical (x+2)(x-3)(x+4) ?

The critical (x+2)(x-3)(x+4) is x=-(3+sqrt(39))/3 ,x=(-3+sqrt(39))/3

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critical (x+2)(x-3)(x+4)

critical points

(x + 2) (x - 3) (x + 4)

x = - \frac{3 + 39}{3}, x = \frac{- 3 + 39}{3}

Solution steps

(x + 2) (x - 3) (x + 4)

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{3 + 39}{3}, x = \frac{- 3 + 39}{3}

Identify critical points not in

f (x)

domain

Domain of

(x + 2) (x - 3) (x + 4) : - \infty < x < \infty

All critical points are in domain

x = - \frac{3 + 39}{3}, x = \frac{- 3 + 39}{3}

(3, - 2), (- 1, - 1)

\frac{x ^{2}}{x - 4}

\frac{( 5 - x )}{( 8 )}

y = 3 x + 29

\frac{x}{x ^{2} + 2}

What is the critical (x+2)(x-3)(x+4) ?
The critical (x+2)(x-3)(x+4) is x=-(3+sqrt(39))/3 ,x=(-3+sqrt(39))/3