What is the extreme f(x)=2x-4sqrt(x-7) ?

The extreme f(x)=2x-4sqrt(x-7) is Minimum(7,14),Maximum(8,12)

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extreme f(x)=2x-4sqrt(x-7)

extreme points

f (x) = 2 x - 4 x - 7

Minimum (7, 14), Maximum (8, 12)

Solution steps

f^{'} (x) = 2 - \frac{2}{x - 7}

Find intervals:

Increasing

: 7 \leq x < 8,

Decreasing

: 8 < x < \infty

Plug

x = 7

into

2 x - 4 x - 7 : 14

Minimum (7, 14)

Plug

x = 8

into

2 x - 4 x - 7 : 12

Maximum (8, 12)

Minimum (7, 14), Maximum (8, 12)

f (x) = \frac{2 x + 1}{2 x}

f (x) = x^{2} lo g_{10} (4) (x)

f (x) = 22 + 13 y \cdot 10 z

f (x) = \frac{- 4}{x - 7}

f (x, y) = 4 x^{2} + 7 x y + 2 y^{2}

What is the extreme f(x)=2x-4sqrt(x-7) ?
The extreme f(x)=2x-4sqrt(x-7) is Minimum(7,14),Maximum(8,12)