What is the extreme f(x)=2x^3-3x^2-12x-18 ?

The extreme f(x)=2x^3-3x^2-12x-18 is Maximum(-1,-11),Minimum(2,-38)

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extreme f(x)=2x^3-3x^2-12x-18

extreme points

f (x) = 2 x^{3} - 3 x^{2} - 12 x - 18

Maximum (- 1, - 11), Minimum (2, - 38)

Solution steps

f^{'} (x) = 6 x^{2} - 6 x - 12

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 1

into

2 x^{3} - 3 x^{2} - 12 x - 18 : - 11

Maximum (- 1, - 11)

Plug

x = 2

into

2 x^{3} - 3 x^{2} - 12 x - 18 : - 38

Minimum (2, - 38)

Maximum (- 1, - 11), Minimum (2, - 38)

f (x, y) = 18 x y - x^{3} - 9 y^{2}

f (x) = 2 x^{3} - 24 x^{2} + 42 x - 6

f (x) = x^{7}

f (x) = 3 x^{2} + 6 x + 8

a \cdot (\frac{π}{2} - x)

What is the extreme f(x)=2x^3-3x^2-12x-18 ?
The extreme f(x)=2x^3-3x^2-12x-18 is Maximum(-1,-11),Minimum(2,-38)