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Popular >

extreme f(x)=16+4x-x^2

Solution

extreme points

f (x) = 16 + 4 x - x^{2}

Solution

Maximum (2, 20)

Solution steps

f^{'} (x) = - 2 x + 4

Find intervals:

Increasing

: - \infty < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = 2

into

16 + 4 x - x^{2} : 20

Maximum (2, 20)

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=16+4x-x^2 ?
The extreme f(x)=16+4x-x^2 is Maximum(2,20)