What is the extreme f(x)= x/(sqrt(x-6)) ?

The extreme f(x)= x/(sqrt(x-6)) is Minimum(12,2sqrt(6))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)= x/(sqrt(x-6))

extreme points

f (x) = \frac{x}{x - 6}

Minimum (12, 26)

Solution steps

f^{'} (x) = \frac{x - 12}{2 ( x - 6 ) x - 6}

Find intervals:

Decreasing

: 6 < x < 12,

Increasing

: 12 < x < \infty

Plug

x = 12

into

\frac{x}{x - 6} : 26

Minimum (12, 26)

f (x) = - x^{2} - 5 x + 2

f (x, y) = x^{2} + y^{2} + 8 x - 12 y - 9

f (x, y) = 2 x y + 3 x + 4 y

f (x, y) = 420 x^{2} - 80 x + 150 y^{2} - 75 y + x y

f (x) = - \frac{2 x}{7 x ^{2} + 4}

What is the extreme f(x)= x/(sqrt(x-6)) ?
The extreme f(x)= x/(sqrt(x-6)) is Minimum(12,2sqrt(6))