What is the extreme f(x)=((x^2-7))/(x+4) ?

The extreme f(x)=((x^2-7))/(x+4) is Maximum(-7,-14),Minimum(-1,-2)

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extreme f(x)=((x^2-7))/(x+4)

extreme points

f (x) = \frac{( x ^{2} - 7 )}{x + 4}

Maximum (- 7, - 14), Minimum (- 1, - 2)

Solution steps

f^{'} (x) = \frac{x ^{2} + 8 x + 7}{( x + 4 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 7,

Decreasing

: - 7 < x < - 4,

Decreasing

: - 4 < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 7

into

\frac{x ^{2} - 7}{x + 4} : - 14

Maximum (- 7, - 14)

Plug

x = - 1

into

\frac{x ^{2} - 7}{x + 4} : - 2

Minimum (- 1, - 2)

Maximum (- 7, - 14), Minimum (- 1, - 2)

f (x) = cos (x) - 4 x, 0 \leq x \leq 4 π

f (x) = - 2 x^{2} + 2 x, - 3 \leq x \leq 2

f (x) = \frac{ln ( x )}{x ^{10}}

f (x, y) = \frac{7}{- 91 x ^{2} - 3 y ^{2} + 9}

f (x, y) = (2 x + 3) (y^{- 1} + 2)

What is the extreme f(x)=((x^2-7))/(x+4) ?
The extreme f(x)=((x^2-7))/(x+4) is Maximum(-7,-14),Minimum(-1,-2)