What is the extreme f(x)=(6x^2)/(x-6),-3<= x<= 2 ?

The extreme f(x)=(6x^2)/(x-6),-3<= x<= 2 is Minimum(-3,-6),Maximum(0,0),Minimum(2,-6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=(6x^2)/(x-6),-3<= x<= 2

extreme points

f (x) = \frac{6 x ^{2}}{x - 6}, - 3 \leq x \leq 2

Minimum (- 3, - 6), Maximum (0, 0), Minimum (2, - 6)

Solution steps

Find the critical points:

x = - 3, x = 0, x = 2

Domain of

\frac{6 x ^{2}}{x - 6}, - 3 \leq x \leq 2 : - 3 \leq x \leq 2

Find intervals:

Increasing

: - 3 < x < 0,

Decreasing

: 0 < x < 2

Plug the extreme point

x = - 3

into

\frac{6 x ^{2}}{x - 6} \Rightarrow y = - 6

Minimum (- 3, - 6)

Plug the extreme point

x = 0

into

\frac{6 x ^{2}}{x - 6} \Rightarrow y = 0

Maximum (0, 0)

Plug the extreme point

x = 2

into

\frac{6 x ^{2}}{x - 6} \Rightarrow y = - 6

Minimum (2, - 6)

Minimum (- 3, - 6), Maximum (0, 0), Minimum (2, - 6)

f (x) = x - 3 x

f (x) = ln (x^{2} + 7 x + 14), - 4 \leq x \leq 1

f (x) = \frac{x - 1}{x - 2}

f (x) = 2 x^{2} - 36 ln (x)

y = x^{2} - 8 x + 12

What is the extreme f(x)=(6x^2)/(x-6),-3<= x<= 2 ?
The extreme f(x)=(6x^2)/(x-6),-3<= x<= 2 is Minimum(-3,-6),Maximum(0,0),Minimum(2,-6)