What is the extreme f(x)=2x-1.75x^2+1.1^3-0.25x^4 ?

The extreme f(x)=2x-1.75x^2+1.1^3-0.25x^4 is Maximum(0.52910…,1.87970…)

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extreme f(x)=2x-1.75x^2+1.1^3-0.25x^4

extreme points

f (x) = 2 x - 1.75 x^{2} + 1. 1^{3} - 0.25 x^{4}

Maximum (0.52910 \dots, 1.87970 \dots)

Solution steps

Find the critical points:

x \approx 0.52910 \dots

Domain of

2 x - 1.75 x^{2} + 1. 1^{3} - 0.25 x^{4} : - \infty < x < \infty

Find intervals:

Increasing

: - \infty < x < 0.52910 \dots,

Decreasing

: 0.52910 \dots < x < \infty

Plug the extreme point

x = 0.52910 \dots

into

2 x - 1.75 x^{2} + 1. 1^{3} - 0.25 x^{4} \Rightarrow y = 1.87970 \dots

Maximum (0.52910 \dots, 1.87970 \dots)

f (x y) = - x^{2} - y^{2} + 22 x + 18 y - 102

x^{2} + 2 x + 1

\frac{x + 4}{x ^{2} - 3 x - 28}

f (x) = ∣ x - 1 ∣

f (x) = x^{2} (180 - 2 x)

What is the extreme f(x)=2x-1.75x^2+1.1^3-0.25x^4 ?
The extreme f(x)=2x-1.75x^2+1.1^3-0.25x^4 is Maximum(0.52910…,1.87970…)