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midpoint
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domain of f(x)=4^xdomain intercepts of (2x-2)/(x+2)intercepts domain of f(x)=(x^2)/(2-x)domain inverse of f(x)=(5-x)^{1/4}inverse parity f(x)=-x^7+9x^3+3xparity
Frequently Asked Questions (FAQ)
What is the midpoint (0,s),(s,0) ?
The midpoint (0,s),(s,0) is (s/2 , s/2)