What is the extreme f(x)=6x^{2/3}-x ?

The extreme f(x)=6x^{2/3}-x is Minimum(0,0),Maximum(64,32)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=6x^{2/3}-x

extreme points

f (x) = 6 x^{\frac{2}{3}} - x

Minimum (0, 0), Maximum (64, 32)

Solution steps

f^{'} (x) = \frac{4}{x ^{\frac{1}{3}}} - 1

Find intervals:

Decreasing

: - \infty < x < \frac{1}{64},

Increasing

: \frac{1}{64} < x < \infty

Plug

x = 0

into

6 x^{\frac{2}{3}} - x : 0

Minimum (0, 0)

Plug

x = 64

into

6 x^{\frac{2}{3}} - x : 32

Maximum (64, 32)

Minimum (0, 0), Maximum (64, 32)

f (x) = - x^{2} - y^{2} + x + 2 y - 1

f (x, y) = 4 x^{4} + 4 y^{4} - 2 x y

f (x) = x^{2} + y^{2} - 4 x = 1

f (x) = x^{3} - 7 x - 6

f (x) = \frac{x}{x ^{2} + 9}, - 5 \leq x \leq 5

What is the extreme f(x)=6x^{2/3}-x ?
The extreme f(x)=6x^{2/3}-x is Minimum(0,0),Maximum(64,32)