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Popular >

extreme f(x)= 3/(x^2-2x)

Solution

extreme points

f (x) = \frac{3}{x ^{2} - 2 x}

Solution

Maximum (1, - 3)

Solution steps

f^{'} (x) = - \frac{3 ( 2 x - 2 )}{( x ^{2} - 2 x ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 0,

Increasing

: 0 < x < 1,

Decreasing

: 1 < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = 1

into

\frac{3}{x ^{2} - 2 x} : - 3

Maximum (1, - 3)

Graph

Popular Examples

extreme P(x,y)=2x+2y-x^2+y^2 extreme points

P (x, y) = 2 x + 2 y - x^{2} + y^{2}

extreme f(x)=x^3-3/2 x^2,-1<= x<= 4 extreme points

f (x) = x^{3} - \frac{3}{2} x^{2}, - 1 \leq x \leq 4

extreme f(x)=2x^3+3x^2+4,-2<= x<= 1 extreme points

f (x) = 2 x^{3} + 3 x^{2} + 4, - 2 \leq x \leq 1

extreme f(x)=x^3+3x^2-24x[0.3]extreme points

f (x) = x^{3} + 3 x^{2} - 24 x [0.3]

extreme f(x)=-2/(x-7)extreme points

f (x) = - \frac{2}{x - 7}

Frequently Asked Questions (FAQ)

What is the extreme f(x)= 3/(x^2-2x) ?
The extreme f(x)= 3/(x^2-2x) is Maximum(1,-3)