What is the range of x/((x+2)(x-3)) ?

The range of x/((x+2)(x-3)) is -infinity <f(x)<infinity

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range of x/((x+2)(x-3))

range

\frac{x}{( x + 2 ) ( x - 3 )}

- \infty < f (x) < \infty

Solution steps

Rewrite as

\frac{x}{( x + 2 ) ( x - 3 )} = y

Multiply both sides by

(x + 2) (x - 3)

x = y (x + 2) (x - 3)

The range is the set of y for which the discriminant is greater or equal to zero

Discriminant

x = y (x + 2) (x - 3) : 25 y^{2} + 2 y + 1

25 y^{2} + 2 y + 1 \geq 0 :

True for all

y \in R

Therefore the range is

- \infty < f (x) < \infty

\frac{x ^{3} + 1 + x ^{2} + x}{∣ x + 1 ∣}

(0) (6 - 2)

f (x) = 7 - 16 t

ln (x^{2} + 7)

\frac{x ^{2}}{x ^{2} + 1}

What is the range of x/((x+2)(x-3)) ?
The range of x/((x+2)(x-3)) is -infinity <f(x)<infinity