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Popular >

extreme y=2x^2-8x+10

Solution

extreme points

y = 2 x^{2} - 8 x + 10

Solution

Minimum (2, 2)

Solution steps

f^{'} (x) = 4 x - 8

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

2 x^{2} - 8 x + 10 : 2

Minimum (2, 2)

Graph

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Frequently Asked Questions (FAQ)

What is the extreme y=2x^2-8x+10 ?
The extreme y=2x^2-8x+10 is Minimum(2,2)