What is the extreme f(x)=168000x-100x^2 ?

The extreme f(x)=168000x-100x^2 is Maximum(840,70560000)

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extreme f(x)=168000x-100x^2

extreme points

f (x) = 168000 x - 100 x^{2}

Maximum (840, 70560000)

Solution steps

f^{'} (x) = 168000 - 200 x

Find intervals:

Increasing

: - \infty < x < 840,

Decreasing

: 840 < x < \infty

Plug

x = 840

into

168000 x - 100 x^{2} : 70560000

Maximum (840, 70560000)

f (x) = x^{2} (6 - x)^{3}

f (x) = x^{2} + x y + y^{2} - 31 y + 320

f (x, y) = - 2 x^{3} - 2 y^{3} - 6 x y + 1

f (x) = 3 e^{x} - x e^{x}

P (x, y) = 3 x^{2} - 8 x y - 3 y^{2}

What is the extreme f(x)=168000x-100x^2 ?
The extreme f(x)=168000x-100x^2 is Maximum(840,70560000)