en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3+12x

Solution

extreme points

f (x) = x^{3} + 12 x

Solution

None

Solution steps

f^{'} (x) = 3 x^{2} + 12

Find intervals:

None

None

Graph

Popular Examples

extreme f(x)=2x^3-6x,0<= x<= 3 extreme points

f (x) = 2 x^{3} - 6 x, 0 \leq x \leq 3

extreme (x^4)/(x^2-1)extreme points

\frac{x ^{4}}{x ^{2} - 1}

extreme f(x,y)=3sqrt(16-x^2-y^2)extreme points

f (x, y) = 3 16 - x^{2} - y^{2}

extreme 1+5/x-9/(x^2)extreme points

1 + \frac{5}{x} - \frac{9}{x ^{2}}

extreme f(x)=x^2+xy+y^2-2x-y extreme points

f (x) = x^{2} + x y + y^{2} - 2 x - y

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^3+12x ?
The extreme f(x)=x^3+12x is None