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Popular >

extreme f(x)=-x^2+x-2

Solution

extreme points

f (x) = - x^{2} + x - 2

Solution

Maximum (\frac{1}{2}, - \frac{7}{4})

Solution steps

f^{'} (x) = - 2 x + 1

Find intervals:

Increasing

: - \infty < x < \frac{1}{2},

Decreasing

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

- x^{2} + x - 2 : - \frac{7}{4}

Maximum (\frac{1}{2}, - \frac{7}{4})

Graph

Popular Examples

extreme-2x^3+3x^2 extreme points

- 2 x^{3} + 3 x^{2}

extreme f(x)=x^3-3x+3,0<= x<= 2 extreme points

f (x) = x^{3} - 3 x + 3, 0 \leq x \leq 2

extreme f(x,y)=2xy-1/2 (x^4+y^4)+1 extreme points

f (x, y) = 2 x y - \frac{1}{2} (x^{4} + y^{4}) + 1

extreme f(x,y)=x+y+1/x+4/y extreme points

f (x, y) = x + y + \frac{1}{x} + \frac{4}{y}

extreme 3x^4-7x^2+6x^2-5x-8 extreme points

3 x^{4} - 7 x^{2} + 6 x^{2} - 5 x - 8

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-x^2+x-2 ?
The extreme f(x)=-x^2+x-2 is Maximum(1/2 ,-7/4)