What is the extreme f(x,y)=x^2+y^2-20x+16y-9 ?

The extreme f(x,y)=x^2+y^2-20x+16y-9 is Minimum(10,-8)

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extreme f(x,y)=x^2+y^2-20x+16y-9

extreme points

f (x, y) = x^{2} + y^{2} - 20 x + 16 y - 9

Minimum (10, - 8)

Solution steps

Find the critical points:

(10, - 8)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = 4

Check the sign of at each critical point

Check critical point

(10, - 8) :

Minimum

Minimum (10, - 8)

4 - 6 x + x^{2}

f (x) = 6 sin (3 x)

f (x) = \frac{e ^{x}}{7 x}

f (x) = 12 + 6 x^{2} - x^{3}

f (x) = \frac{3 x ^{2}}{2}

What is the extreme f(x,y)=x^2+y^2-20x+16y-9 ?
The extreme f(x,y)=x^2+y^2-20x+16y-9 is Minimum(10,-8)