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Popular >

extreme f(x)=-1-x+x^2

Solution

extreme points

f (x) = - 1 - x + x^{2}

Solution

Minimum (\frac{1}{2}, - \frac{5}{4})

Solution steps

f^{'} (x) = 2 x - 1

Find intervals:

Decreasing

: - \infty < x < \frac{1}{2},

Increasing

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

- 1 - x + x^{2} : - \frac{5}{4}

Minimum (\frac{1}{2}, - \frac{5}{4})

Graph

Popular Examples

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extreme x^{1/5}(x+6)extreme points

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extreme f(x)=(x+1)^5-5x-2 extreme points

f (x) = (x + 1)^{5} - 5 x - 2

extreme f(x)=5x^5-3x^3 extreme points

f (x) = 5 x^{5} - 3 x^{3}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-1-x+x^2 ?
The extreme f(x)=-1-x+x^2 is Minimum(1/2 ,-5/4)