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Popular >

extreme f(x)=4x^2-8x+3

Solution

extreme points

f (x) = 4 x^{2} - 8 x + 3

Solution

Minimum (1, - 1)

Solution steps

f^{'} (x) = 8 x - 8

Find intervals:

Decreasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

4 x^{2} - 8 x + 3 : - 1

Minimum (1, - 1)

Graph

Popular Examples

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extreme (x^2+3x-1)^{1/3}extreme points

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f (x) = x (27 - 41 + 2 x) (\frac{41}{2} - x)

Frequently Asked Questions (FAQ)

What is the extreme f(x)=4x^2-8x+3 ?
The extreme f(x)=4x^2-8x+3 is Minimum(1,-1)