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Popular >

extreme f(x)=(x^2)/(x^2+48)

Solution

extreme points

f (x) = \frac{x ^{2}}{x ^{2} + 48}

Solution

Minimum (0, 0)

Solution steps

f^{'} (x) = \frac{96 x}{( x ^{2} + 48 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

\frac{x ^{2}}{x ^{2} + 48} : 0

Minimum (0, 0)

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x^2)/(x^2+48) ?
The extreme f(x)=(x^2)/(x^2+48) is Minimum(0,0)