What is the extreme f(x)=(x-1)(x+2)(x+5) ?

The extreme f(x)=(x-1)(x+2)(x+5) is Maximum(-2-sqrt(3),6sqrt(3)),Minimum(-2+sqrt(3),-6sqrt(3))

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extreme f(x)=(x-1)(x+2)(x+5)

extreme points

f (x) = (x - 1) (x + 2) (x + 5)

Maximum (- 2 - 3, 63), Minimum (- 2 + 3, - 63)

Solution steps

f^{'} (x) = 3 (x^{2} + 4 x + 1)

Find intervals:

Increasing

: - \infty < x < - 3 - 2,

Decreasing

: - 3 - 2 < x < 3 - 2,

Increasing

: 3 - 2 < x < \infty

Plug

x = - 2 - 3

into

(x - 1) (x + 2) (x + 5) : 63

Maximum (- 2 - 3, 63)

Plug

x = - 2 + 3

into

(x - 1) (x + 2) (x + 5) : - 63

Minimum (- 2 + 3, - 63)

Maximum (- 2 - 3, 63), Minimum (- 2 + 3, - 63)

f (x) = - \frac{x ^{2}}{2} - 3 x - \frac{11}{2}

f (x, y) = x^{3} + y^{3} - x y

f (x, y) = e^{2 x} (x + y^{2} + 2 y)

f (x) = \frac{2 x ^{\frac{5}{2}}}{5} - \frac{2 x ^{\frac{3}{2}}}{3} - 1

f (x) = x^{\frac{4}{3}} - x^{\frac{2}{3}}

What is the extreme f(x)=(x-1)(x+2)(x+5) ?
The extreme f(x)=(x-1)(x+2)(x+5) is Maximum(-2-sqrt(3),6sqrt(3)),Minimum(-2+sqrt(3),-6sqrt(3))