What is the inverse of y=(7-8x)^2 ?

The inverse of y=(7-8x)^2 is -(sqrt(x)-7)/8 ,-(-sqrt(x)-7)/8

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inverse of y=(7-8x)^2

inverse

y = (7 - 8 x)^{2}

- \frac{x - 7}{8}, - \frac{- x - 7}{8}

Solution steps

y = (7 - 8 x)^{2}

Replace

x

with

y

x = (7 - 8 y)^{2}

Solve for

y, x = (7 - 8 y)^{2}

- \frac{x - 7}{8}, - \frac{- x - 7}{8}

y = x^{2} + 2 x - 1

f (x) = 49 x + 72

f (x) = \frac{x ^{2} - 11 x - 12}{x + 4}

f (x) = x^{2} + 8 x + 1

What is the inverse of y=(7-8x)^2 ?
The inverse of y=(7-8x)^2 is -(sqrt(x)-7)/8 ,-(-sqrt(x)-7)/8