What is the extreme (x^3+38x+128)/x ,1<= x<= 10 ?

The extreme (x^3+38x+128)/x ,1<= x<= 10 is Maximum(1,167),Minimum(4,86),Maximum(10, 754/5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme (x^3+38x+128)/x ,1<= x<= 10

extreme points

\frac{x ^{3} + 38 x + 128}{x}, 1 \leq x \leq 10

Maximum (1, 167), Minimum (4, 86), Maximum (10, \frac{754}{5})

Solution steps

Find the critical points:

x = 1, x = 4, x = 10

Domain of

\frac{x ^{3} + 38 x + 128}{x}, 1 \leq x \leq 10 : 1 \leq x \leq 10

Find intervals:

Decreasing

: 1 < x < 4,

Increasing

: 4 < x < 10

Plug the extreme point

x = 1

into

\frac{x ^{3} + 38 x + 128}{x} \Rightarrow y = 167

Maximum (1, 167)

Plug the extreme point

x = 4

into

\frac{x ^{3} + 38 x + 128}{x} \Rightarrow y = 86

Minimum (4, 86)

Plug the extreme point

x = 10

into

\frac{x ^{3} + 38 x + 128}{x} \Rightarrow y = \frac{754}{5}

Maximum (10, \frac{754}{5})

Maximum (1, 167), Minimum (4, 86), Maximum (10, \frac{754}{5})

x^{2} + 9

\frac{1}{x + 6}

3 x e^{y} - x^{3} - e^{3 y}

f (x) = x^{3} + 3 x^{2} - 24 x, 0 \leq x \leq 3

f (x) = 2 cos^{2} (x), (0, π)

What is the extreme (x^3+38x+128)/x ,1<= x<= 10 ?
The extreme (x^3+38x+128)/x ,1<= x<= 10 is Maximum(1,167),Minimum(4,86),Maximum(10, 754/5)