What is the extreme f(x)=2x^3-33x^2+180x+6 ?

The extreme f(x)=2x^3-33x^2+180x+6 is Maximum(5,331),Minimum(6,330)

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extreme f(x)=2x^3-33x^2+180x+6

extreme points

f (x) = 2 x^{3} - 33 x^{2} + 180 x + 6

Maximum (5, 331), Minimum (6, 330)

Solution steps

f^{'} (x) = 6 x^{2} - 66 x + 180

Find intervals:

Increasing

: - \infty < x < 5,

Decreasing

: 5 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 5

into

2 x^{3} - 33 x^{2} + 180 x + 6 : 331

Maximum (5, 331)

Plug

x = 6

into

2 x^{3} - 33 x^{2} + 180 x + 6 : 330

Minimum (6, 330)

Maximum (5, 331), Minimum (6, 330)

f (x) = (x^{4} - 32 x^{2} - 4)

f (x) = 5 x^{3} e^{- x}, - 1 \leq x \leq 4

f (x, y) = x^{2} + 2 x + y^{2} - 8 y + 8

f (x) = x^{2} \cdot e^{x} - 2 x \cdot e^{x} + 2 e^{x}

f (x) = \frac{x ^{3} + 4}{x ^{2}}

What is the extreme f(x)=2x^3-33x^2+180x+6 ?
The extreme f(x)=2x^3-33x^2+180x+6 is Maximum(5,331),Minimum(6,330)