What is the extreme f(x)= 1/4 x^2-1/2 x+13/4 ?

The extreme f(x)= 1/4 x^2-1/2 x+13/4 is Minimum(1,3)

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extreme f(x)= 1/4 x^2-1/2 x+13/4

extreme points

f (x) = \frac{1}{4} x^{2} - \frac{1}{2} x + \frac{13}{4}

Minimum (1, 3)

Solution steps

f^{'} (x) = \frac{x - 1}{2}

Find intervals:

Decreasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

\frac{1}{4} x^{2} - \frac{1}{2} x + \frac{13}{4} : 3

Minimum (1, 3)

f (x) = 6 x^{2} - 12 [- 4.1]

7 x^{5} - 105 x^{3}

f (x) = x^{3} - 9 x^{2} + 15 x + 7

f (x) = \frac{6 x - 1}{x}

f (x) = x^{2} \cdot (2 - x)^{2}

What is the extreme f(x)= 1/4 x^2-1/2 x+13/4 ?
The extreme f(x)= 1/4 x^2-1/2 x+13/4 is Minimum(1,3)