What is the extreme f(x)=(x-y)(xy-1) ?

The extreme f(x)=(x-y)(xy-1) is Saddle(1,1),Saddle(-1,-1)

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extreme f(x)=(x-y)(xy-1)

extreme points

f (x) = (x - y) (x y - 1)

Saddle (1, 1), Saddle (- 1, - 1)

Solution steps

Find the critical points:

(1, 1), (- 1, - 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2 x

D (x, y) = - 4 x^{2} + 4 x y - 4 y^{2}

Check the sign of at each critical point

Check critical point

(1, 1) :

Saddle

Check critical point

(- 1, - 1) :

Saddle

Saddle (1, 1), Saddle (- 1, - 1)

F (x, y) = x^{2} y^{3} - x y - y

f (x) = \frac{x}{x - 9}

sin^{4} (x)

f (x, y) = 15 x^{2} + 16 y^{2}

f (x) = \frac{x}{x - 5}

What is the extreme f(x)=(x-y)(xy-1) ?
The extreme f(x)=(x-y)(xy-1) is Saddle(1,1),Saddle(-1,-1)