What is the extreme f(x)=-2x^4+20x^2-18 ?

The extreme f(x)=-2x^4+20x^2-18 is Maximum(-sqrt(5),32),Minimum(0,-18),Maximum(sqrt(5),32)

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extreme f(x)=-2x^4+20x^2-18

extreme points

f (x) = - 2 x^{4} + 20 x^{2} - 18

Maximum (- 5, 32), Minimum (0, - 18), Maximum (5, 32)

Solution steps

f^{'} (x) = - 8 x^{3} + 40 x

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 0,

Increasing

: 0 < x < 5,

Decreasing

: 5 < x < \infty

Plug

x = - 5

into

- 2 x^{4} + 20 x^{2} - 18 : 32

Maximum (- 5, 32)

Plug

x = 0

into

- 2 x^{4} + 20 x^{2} - 18 : - 18

Minimum (0, - 18)

Plug

x = 5

into

- 2 x^{4} + 20 x^{2} - 18 : 32

Maximum (5, 32)

Maximum (- 5, 32), Minimum (0, - 18), Maximum (5, 32)

f (x, y) = - x^{2} - y^{2} + 20 x + 20 y

f (x) = x + \frac{9}{x} + 4, 1 \leq x \leq 18

f (x) = - 2 x + 3 ln (2 x)

f (x, y) = 2 - x + y

f (x) = 16 x + 9 x^{- 1}

What is the extreme f(x)=-2x^4+20x^2-18 ?
The extreme f(x)=-2x^4+20x^2-18 is Maximum(-sqrt(5),32),Minimum(0,-18),Maximum(sqrt(5),32)