What is the extreme f(x)=x^3-9x^2+7 ?

The extreme f(x)=x^3-9x^2+7 is Maximum(0,7),Minimum(6,-101)

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extreme f(x)=x^3-9x^2+7

extreme points

f (x) = x^{3} - 9 x^{2} + 7

Maximum (0, 7), Minimum (6, - 101)

Solution steps

f^{'} (x) = 3 x^{2} - 18 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 0

into

x^{3} - 9 x^{2} + 7 : 7

Maximum (0, 7)

Plug

x = 6

into

x^{3} - 9 x^{2} + 7 : - 101

Minimum (6, - 101)

Maximum (0, 7), Minimum (6, - 101)

30 x^{3} - 19 x^{2} - 14 x + 8

f (x) = x^{3} - 2

f (x) = 1 - x^{2}, 0 \leq x \leq 1

2 x^{2} + 12 x - 2

f (x, y) = x e^{- x} + y e^{- 2 y}

What is the extreme f(x)=x^3-9x^2+7 ?
The extreme f(x)=x^3-9x^2+7 is Maximum(0,7),Minimum(6,-101)