What is the extreme f(x)=3x+(48)/x ?

The extreme f(x)=3x+(48)/x is Maximum(-4,-24),Minimum(4,24)

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extreme f(x)=3x+(48)/x

extreme points

f (x) = 3 x + \frac{48}{x}

Maximum (- 4, - 24), Minimum (4, 24)

Solution steps

f^{'} (x) = 3 - \frac{48}{x ^{2}}

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < 0,

Decreasing

: 0 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 4

into

3 x + \frac{48}{x} : - 24

Maximum (- 4, - 24)

Plug

x = 4

into

3 x + \frac{48}{x} : 24

Minimum (4, 24)

Maximum (- 4, - 24), Minimum (4, 24)

f (x, y) = x^{2} + x y + y^{2} + \frac{3}{x} + \frac{3}{y} + 2

y = 2 + s + 2 (- 3 - 2 s + x)

f (x, y) = 3 x y + x y^{2}

f (x, y) = 4 + x^{3} - 3 x y + y^{3}

f (x) = x^{4} (1 - x)^{8}

What is the extreme f(x)=3x+(48)/x ?
The extreme f(x)=3x+(48)/x is Maximum(-4,-24),Minimum(4,24)