What is the extreme f(x)=-xe^{-x/4} ?

The extreme f(x)=-xe^{-x/4} is Minimum(4,-4/e)

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extreme f(x)=-xe^{-x/4}

extreme points

f (x) = - x e^{- \frac{x}{4}}

Minimum (4, - \frac{4}{e})

Solution steps

Find the critical points:

x = 4

Domain of

- x e^{- \frac{x}{4}} : - \infty < x < \infty

Find intervals:

Decreasing

: - \infty < x < 4,

Increasing

: 4 < x < \infty

Plug the extreme point

x = 4

into

- x e^{- \frac{x}{4}} \Rightarrow y = - \frac{4}{e}

Minimum (4, - \frac{4}{e})

f (x) = 2 x^{3} + 6 x^{2} - 18 x + 1, - 6 \leq x \leq 2

f (x, y) = x^{2} + y^{2} - 12 x + 4 y - 11

f (x) = 6 x + 7 x^{(\frac{6}{7})}

f (x) = 49 x + \frac{9}{x}

x (2^{- 5 x})

What is the extreme f(x)=-xe^{-x/4} ?
The extreme f(x)=-xe^{-x/4} is Minimum(4,-4/e)