What is the extreme f(x,y)=-2x^2+5y^2-9x+9y+6 ?

The extreme f(x,y)=-2x^2+5y^2-9x+9y+6 is Saddle(-9/4 ,-9/10)

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extreme f(x,y)=-2x^2+5y^2-9x+9y+6

extreme points

f (x, y) = - 2 x^{2} + 5 y^{2} - 9 x + 9 y + 6

Saddle (- \frac{9}{4}, - \frac{9}{10})

Solution steps

Find the critical points:

(- \frac{9}{4}, - \frac{9}{10})

\frac{\partial ^{2} f}{\partial x ^{2}} = 10

D (x, y) = - 40

Check the sign of at each critical point

Check critical point

(- \frac{9}{4}, - \frac{9}{10}) :

Saddle

Saddle (- \frac{9}{4}, - \frac{9}{10})

f (x) = x^{3} + y^{2} - 3 x - 4 y + 7

x^{5} - 15 x^{3} + 3

h (x) = \frac{θ x ^{4} + 3 θ x ^{3} + 3 θ x ^{2} + θ x}{x ^{3} + 2 x ^{2} + x}

f (x, y) = (x^{2} + 2 y^{2}) e^{1 - x^{2} - y^{2}}

f (x) = (16 - 2 x) (12 - 2 x) x

What is the extreme f(x,y)=-2x^2+5y^2-9x+9y+6 ?
The extreme f(x,y)=-2x^2+5y^2-9x+9y+6 is Saddle(-9/4 ,-9/10)