What is the extreme f(x,y)=x^2+xy+y^2-2x-y ?

The extreme f(x,y)=x^2+xy+y^2-2x-y is Minimum(1,0)

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extreme f(x,y)=x^2+xy+y^2-2x-y

extreme points

f (x, y) = x^{2} + x y + y^{2} - 2 x - y

Minimum (1, 0)

Solution steps

Find the critical points:

(1, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = 3

Check the sign of at each critical point

Check critical point

(1, 0) :

Minimum

Minimum (1, 0)

V (A, t) = A^{t}

f (x) = x^{3} + 32 x^{2} - 6 x + 8, - 4 \leq x \leq 2

f (x) = x + \frac{x}{9}

280

x^{4} + 3 x^{3} - 5 x^{2} - 6 x + 6

What is the extreme f(x,y)=x^2+xy+y^2-2x-y ?
The extreme f(x,y)=x^2+xy+y^2-2x-y is Minimum(1,0)