What is the extreme f(x)=(x^2+80)/(x+8) ?

The extreme f(x)=(x^2+80)/(x+8) is Maximum(-20,-40),Minimum(4,8)

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extreme f(x)=(x^2+80)/(x+8)

extreme points

f (x) = \frac{x ^{2} + 80}{x + 8}

Maximum (- 20, - 40), Minimum (4, 8)

Solution steps

f^{'} (x) = \frac{x ^{2} + 16 x - 80}{( x + 8 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 20,

Decreasing

: - 20 < x < - 8,

Decreasing

: - 8 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 20

into

\frac{x ^{2} + 80}{x + 8} : - 40

Maximum (- 20, - 40)

Plug

x = 4

into

\frac{x ^{2} + 80}{x + 8} : 8

Minimum (4, 8)

Maximum (- 20, - 40), Minimum (4, 8)

f (x, y) = x^{2} + y^{2} - 2 x + 14 y - 11

f (x) = - 3 x^{2} + 30 x - 4

\frac{9 e ^{x}}{1 + e ^{- x}}

f (x) = 81 x - 3 x^{3}

F (x, y) = y^{2} - x^{2}

What is the extreme f(x)=(x^2+80)/(x+8) ?
The extreme f(x)=(x^2+80)/(x+8) is Maximum(-20,-40),Minimum(4,8)