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Popular >

extreme f(x)=sqrt(4x+12)

Solution

extreme points

f (x) = 4 x + 12

Solution

Minimum (- 3, 0)

Solution steps

f^{'} (x) = \frac{1}{x + 3}

Find intervals:

Increasing

: - 3 < x < \infty

Plug

x = - 3

into

4 x + 12 : 0

Minimum (- 3, 0)

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=sqrt(4x+12) ?
The extreme f(x)=sqrt(4x+12) is Minimum(-3,0)