What is the extreme f(x)=(4e^{-2x})/(2x+5) ?

The extreme f(x)=(4e^{-2x})/(2x+5) is Maximum(-3,-4e^6)

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extreme f(x)=(4e^{-2x})/(2x+5)

extreme points

f (x) = \frac{4 e ^{- 2 x}}{2 x + 5}

Maximum (- 3, - 4 e^{6})

Solution steps

Find the critical points:

x = - 3

Domain of

\frac{4 e ^{- 2 x}}{2 x + 5} : x < - \frac{5}{2} or x > - \frac{5}{2}

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < - \frac{5}{2},

Decreasing

: - \frac{5}{2} < x < \infty

Plug the extreme point

x = - 3

into

\frac{4 e ^{- 2 x}}{2 x + 5} \Rightarrow y = - 4 e^{6}

Maximum (- 3, - 4 e^{6})

f (x) = (3 - x) (x - 5)^{2}

(X^{2} - 1) (X^{2} - 9)

f (x) = \frac{x}{8 x + 3}, 8 \leq x \leq 12

f (x) = (x^{2} + 4) (16 - x^{2})

f (x) = x^{4} + x^{3} - 3 x^{2} + 1

What is the extreme f(x)=(4e^{-2x})/(2x+5) ?
The extreme f(x)=(4e^{-2x})/(2x+5) is Maximum(-3,-4e^6)