What is the extreme f(x,y)=3x^2-2y^2 ?

The extreme f(x,y)=3x^2-2y^2 is Saddle(0,0)

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extreme f(x,y)=3x^2-2y^2

extreme points

f (x, y) = 3 x^{2} - 2 y^{2}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 4

D (x, y) = - 24

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

K (r, s) = 4 r - 9 s

f (x, y) = 3 x y - x^{3} + y^{3}

f (x) = 0.6 x^{2} - 660 x - 6000

f (x) = \frac{x ^{2} - 1}{x ^{3}}

f (x, y) = e^{- y} \cdot (x^{2} + y^{2})

What is the extreme f(x,y)=3x^2-2y^2 ?
The extreme f(x,y)=3x^2-2y^2 is Saddle(0,0)