What is the extreme T(x,y)=46-2x^2-3y^2 ?

The extreme T(x,y)=46-2x^2-3y^2 is Maximum(0,0)

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extreme T(x,y)=46-2x^2-3y^2

extreme points

T (x, y) = 46 - 2 x^{2} - 3 y^{2}

Maximum (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 6

D (x, y) = 24

Check the sign of at each critical point

Check critical point

(0, 0) :

Maximum

Maximum (0, 0)

f (x) = (- x^{\frac{2}{3}}) (x - 3)

f (x, y) = 2 y^{2} + 2 x y + x^{2} - 16 x - 20 y

f (x) = f (x, y) = 3 x^{3} - 9 x + 9 x y^{2}

f (x) = 5 x + 5 x^{- 1}

x + 2 sin (x)

What is the extreme T(x,y)=46-2x^2-3y^2 ?
The extreme T(x,y)=46-2x^2-3y^2 is Maximum(0,0)