What is the critical f(x)=t^4-16t^3+22t^2 ?

The critical f(x)=t^4-16t^3+22t^2 is t=0,t=1,t=11

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=t^4-16t^3+22t^2

critical points

f (x) = t^{4} - 16 t^{3} + 22 t^{2}

t = 0, t = 1, t = 11

Solution steps

t^{4} - 16 t^{3} + 22 t^{2}

Find where

f^{'} (t)

is equal to zero or undefined

t = 0, t = 1, t = 11

Identify critical points not in

f (t)

domain

Domain of

t^{4} - 16 t^{3} + 22 t^{2} : - \infty < t < \infty

All critical points are in domain

t = 0, t = 1, t = 11

f (x) = - (x + 1)^{3} - 2

f (x) = x^{2} - 6 x + 5

f (x) = 12 x^{3} - 35

- 3 x^{4} - 14 x^{3} - 16 x^{2} - 2 x + 3

y - 4 = - \frac{1}{10} (x - 10)

What is the critical f(x)=t^4-16t^3+22t^2 ?
The critical f(x)=t^4-16t^3+22t^2 is t=0,t=1,t=11