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Popular >

extreme f(t)=-0.01t^2+4t

Solution

extreme points

f (t) = - 0.01 t^{2} + 4 t

Solution

Maximum (200, 400)

Solution steps

f^{'} (t) = - 0.02 t + 4

Find intervals:

Increasing

: - \infty < t < 200,

Decreasing

: 200 < t < \infty

Plug

t = 200

into

- 0.01 t^{2} + 4 t : 400

Maximum (200, 400)

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Frequently Asked Questions (FAQ)

What is the extreme f(t)=-0.01t^2+4t ?
The extreme f(t)=-0.01t^2+4t is Maximum(200,400)